Question

Factor b12 + 8.



(b4- 2)(b16+ 2b4+ 4)
(b4+ 2)(b8- 2b4+ 4)
(b4- 2)(b8+ 2b4+ 4)
(b4+ 2)(b16- 2b4+ 4)

Answer 1

it is b^12 +8?

Answer 2

yes

Answer 3

you can write it as:

\[(b^4)^3 + (2)^3\]

Now use the formula:

\[x^3 + y^3 = (x+y)(x^2 - xy + y^2)\]

Here:

\[x = b^4 \quad and \quad y = 2\]