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Physics 20 Online
OpenStudy (imtant):

Anyone? Find the value of P that will make the box in the figure began to move. The box weight is 300 N and P is parallel to the x axis. Coefficient of static friction is 0.3.

OpenStudy (imtant):

OpenStudy (imtant):

Help me.

OpenStudy (imtant):

Hi..Can you help me?

OpenStudy (saisaith):

Are you using 10 or 9.80 when it comes to little g?

OpenStudy (imtant):

I use 9.80.

OpenStudy (anonymous):

have you drawn your forces at the diagram?

OpenStudy (anonymous):

i need to show you the forces at a diagram and i cant find a program i can draw on...but you should see that the forces exerted on the ''box'' are the Friction Force T that makes ''more difficult'' the movement of the box going down, the weight of the box that is pointing exactly downwards and the P force we want to exert to make the box move that is parallel to the x-axis

OpenStudy (anonymous):

then you will get that Pcos20 + T > mgsin20 --->Pcos20>mgsin20-T and you will see why the angles are like that only if you draw the diagram

OpenStudy (imtant):

Is that all the solving?but how about the coefficient of the static force?when i need to use it?

OpenStudy (anonymous):

ah plug that in Τ=μΝ=μmgcos20

OpenStudy (imtant):

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OpenStudy (anonymous):

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