Question

Find the roots.

2x^2 + 4x - 5 =0

Answer 1

2x^2+4x-5=0
x^2+2x-5/2=0
x^2+2x+1-1-5/2=0
(x+1)^2=1+5/2=7/2
x+1=\[\pm \sqrt{\frac{ 7 }{ 2 }}\]
x=-1\[\pm \frac{ 7 }{ 2 }\]