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Mathematics 7 Online
OpenStudy (anonymous):

Please help! A bacteria culture starts with 500 bacteria and doubles every 3.5 hours. Find an expression for the number of bacteria after t hours. a.550e^35t b.500=Qoe^(ln2)/(3.5)(t) c.500e^(ln2)/(3.5)(t) d.2e^3.5t

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