What is √(14q) x 2 √(4q) ? Can you show me how you got it
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OpenStudy (anonymous):
@jim_thompson5910 help?
jimthompson5910 (jim_thompson5910):
\[\large \sqrt{14q}\times 2\sqrt{4q}\]
\[\large 2\sqrt{14q}\times\sqrt{4q}\]
\[\large 2\sqrt{14q*4q}\]
\[\large 2\sqrt{56q^2}\]
\[\large 2\sqrt{14*4q^2}\]
\[\large 2\sqrt{4q^2*14}\]
\[\large 2\sqrt{4q^2}*\sqrt{14}\]
I'll let you finish up
OpenStudy (anonymous):
\[2\sqrt{56q ^{2}}\] ?
jimthompson5910 (jim_thompson5910):
i already have that step (see line 4)
jimthompson5910 (jim_thompson5910):
but notice how I moved on from it (so that means that it's not completely simplified there)
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OpenStudy (anonymous):
I dont understand how to do more then that. sorry
jimthompson5910 (jim_thompson5910):
how would you simplify \[\large \sqrt{4q^2}\]
OpenStudy (anonymous):
2q?
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
\[\large \sqrt{14q}\times 2\sqrt{4q}\]
\[\large 2\sqrt{14q}\times\sqrt{4q}\]
\[\large 2\sqrt{14q*4q}\]
\[\large 2\sqrt{56q^2}\]
\[\large 2\sqrt{14*4q^2}\]
\[\large 2\sqrt{4q^2*14}\]
\[\large 2\sqrt{4q^2}*\sqrt{14}\]
\[\large 2*2q*\sqrt{14}\]
\[\large 4q*\sqrt{14}\]
and that's all we can do
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