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use the exact value of sin(75) to find sin (105) by using sin(180-75)
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\[\sin(75)=\sin(45+30)=\sin45\cos30+\sin30\cos45=\frac{\sqrt{6}}{4}+\frac{\sqrt{2}}{4}\] So, \[\sin(105)=\sin(180-75)=\sin180\cos75-\sin75\cos180=\sin75=\frac{\sqrt{6}}{4}+\frac{\sqrt{2}}{4}\]
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