Mathematics
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OpenStudy (anonymous):
what is the solution set of x² + 8x + 12 = 0?
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jimthompson5910 (jim_thompson5910):
Hint:
x^2 + 8x + 12 factors to (x+6)(x+2)
OpenStudy (anonymous):
so is it (2,6)
jimthompson5910 (jim_thompson5910):
close, but not quite
OpenStudy (anonymous):
(-2,-6)?
jimthompson5910 (jim_thompson5910):
(x+6)(x+2) = 0
x+6=0 or x+2=0
x = ?? or x = ??
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jimthompson5910 (jim_thompson5910):
yep, x = -2 or x = -6
OpenStudy (anonymous):
thank you so much !
jimthompson5910 (jim_thompson5910):
np
OpenStudy (anonymous):
what about.... equivalent form of the equation t²+5t-24=0?
jimthompson5910 (jim_thompson5910):
factor the left side
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OpenStudy (anonymous):
alright then?...
jimthompson5910 (jim_thompson5910):
what do you get when you factor
OpenStudy (anonymous):
i have no idea honestly lol
jimthompson5910 (jim_thompson5910):
find two numbers that
a) multiply to -24
AND
b) add to 5
OpenStudy (anonymous):
ummm idk :(
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jimthompson5910 (jim_thompson5910):
list out the factors of -24 and the possible ways to multiply to -24
jimthompson5910 (jim_thompson5910):
then add each pair of factors
OpenStudy (anonymous):
12 and 2...6 and 4...8 and 3
jimthompson5910 (jim_thompson5910):
since -24 is negative, one of the factors must be negative (the other must be positive)
OpenStudy (anonymous):
im so lost can you just tell me what it would look like ?...
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OpenStudy (anonymous):
(t + 8)(t - 3) = 0
(t - 8)(t + 3) = 0
(t - 8)(t - 3) = 0
OpenStudy (anonymous):
those are the choices ?
jimthompson5910 (jim_thompson5910):
8 and -3 both
a) multiply to -24
AND
b) add to 5