Question

In a cricket match, five batsmen A, B, C, D and E scored an average of 36 runs. D Scored 5 more than E; E scored 8 fewer than A; B scored as many as D and E combined; and B and C scored 107 between them. How many runs did E score ?
A. 62 B. 45
C. 28 D. 20

Answer 1

@Noemi95

Answer 2

so Aruns + Bruns + Cruns+Druns +Eruns/5=36. Alot of subbing here E+5=D A-8=E B=D+E B+C=107.

It looks like the common variable we can get here is E. So sub till you get the original equation all in E.

Answer 3

How ?

Answer 4

ok. (A) E+8 + (b+c) 107 + (D) E+5 +E/5=36

Answer 5

bueno?