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Mathematics 15 Online
OpenStudy (anonymous):

http://prntscr.com/127a32 I got B wrong

OpenStudy (anonymous):

Cos 270 =0 and Sec 270=1/0 Answer will be Undefined

sam (.sam.):

Yup its undefined, \[\sec(-270) \\ \\ =\frac{1}{\cos(-270)} = undefined\]

OpenStudy (anonymous):

http://prntscr.com/127a92 http://prntscr.com/127aaj i marked D and got it wrong

OpenStudy (anonymous):

@.Sam.

sam (.sam.):

OpenStudy (anonymous):

So B

sam (.sam.):

Yeah

OpenStudy (anonymous):

http://prntscr.com/127ax4

OpenStudy (anonymous):

i marked D because we can see that oscillations are not periodic

OpenStudy (anonymous):

@.Sam.

sam (.sam.):

There is a period if you look closely

sam (.sam.):

It's A, about 6 for period

OpenStudy (anonymous):

http://prntscr.com/127bg5

OpenStudy (anonymous):

I marked C got it wrong

OpenStudy (anonymous):

@.Sam.

sam (.sam.):

Amplitude is 6

sam (.sam.):

amplitude can't be negative. Amplitude is the distance from the median to the maximum or minimum.

sam (.sam.):

Others are correct, so its B

OpenStudy (anonymous):

http://prntscr.com/127f30

OpenStudy (anonymous):

http://prntscr.com/127f4b

OpenStudy (anonymous):

I select ed A

OpenStudy (anonymous):

@.Sam.

OpenStudy (anonymous):

But i think it C

OpenStudy (anonymous):

@.Sam.

sam (.sam.):

Can you see the transformation?

sam (.sam.):

The negative flips the graph

OpenStudy (anonymous):

So B

sam (.sam.):

Yes

OpenStudy (anonymous):

http://prntscr.com/127f9r

OpenStudy (anonymous):

I selected C but its wrong

OpenStudy (anonymous):

@.Sam.

sam (.sam.):

The middle point of that graph should be 25, so the equation should add 25, something like y=sin(x)+25 And there is amplitude of 20, count the peak = 45 and middle = 25, so 45-25=20

OpenStudy (anonymous):

so B

sam (.sam.):

So its something like y=20sin(x)+25

sam (.sam.):

yes

OpenStudy (anonymous):

thanks a lot

sam (.sam.):

Welcome :)

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