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How many numbers less than 100 are the product of 3 distinct primes?
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Starting with the product of the first 2 primes, I'd divide that into 100 to find the maximum 3rd prime value: 100/6 = 16 2/3 So the 3rd prime would have to be less than 16 2/3 So the products of 6 with the remaining primes are: 30, 42, 66, 78 The next smallest product pair would be 10, and the remaining prime products would be: 70 So I'd say "5 numbers less than 100 are the product of 3 distinct primes". Final answer. :-)
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