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\[\frac{ 4 }{ x - 1 } = \frac{ x + 1 }{ 12 }\]
ok
nvm
i wanna try it
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\[\frac{ 4 }{ x-1 }=\frac{ x+1 }{ 12 }\]
or\[(x+1)(x-1)=4 \times 12\]
or\[x ^{2}-1=48\]
or\[x ^{2}=48+1\]
or\[x ^{2}=49\]
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or\[x=7, -7\]
did you take the square root or what
@ajprincess Is he right?
ya he is:) taking square root both sides leave u with that answer:)
thanks so much @ajprincess I might need you again this afternoon of some more math problems
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ya i took square root
welcome:) will try my best to help:)
awesome
i also wanna try to so;veur problem
if i can
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