Ask your own question, for FREE!
Chemistry 13 Online
OpenStudy (anonymous):

C4H5O5 + 3NaHCO3 -> C4H2Na3O5+ 3H2O + 3CO2 How much malic acid (C4H5O5) to be used? Show calculation; give the result in g Information: 500g sodium bicarbonat (NaHCO3)(MW: 84 g/mol). Maleic acid (MW: 134 g/mol) used 1.1 times more of the substance quantity of the acid than the base

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!