Question

the ages of edna, ellie, elsa are consecutive intergers . the sum of their ages is 108. what are their ages?

Answer 1

if call the middle age m
then the 3 ages will be m-1 , m and m+1
add them up and you get 108

in other words
m-1 + m + m+1 = 108

can you find m, and then m-1 and m+1 ?

Answer 2

i dont quite understand this?

Answer 3

can you simplify
m-1 + m + m+1 = 108
?
using algebra

Answer 4

i tried and no.

Answer 5

you can re-arrange things when you add them (order does not matter)
so
m-1 + m + m+1 = 108
is the same as

m+m+m + 1 + -1 = 108

surely you know what 1+ -1 is ???

Answer 6

yes i do ... 0

Answer 7

so you now have
m+m+m+0 = 108

adding 0 on the left side does not change anything, so it is the same as
m+m+m= 108

if 3 m's add up to 108, what do you figure 1 m is ?

Answer 8

if 3 m's are 108, and each m is the same amount, how much is 1 m ?

Answer 9

if 3 sodas cost a total of 6.00 , how much did one soda cost ? (this is the same problem, and you use the same idea to solve your "m" problem)

Answer 10

3.00

Answer 11

no no wait im wrong

Answer 12

2.00

Answer 13

I hope you meant 2.00

I would do 6.00/3 which gives 2.00

do the same for

3m = 108

Answer 14

btw, m+m+m is the same a 3*m (3 times m)

Answer 15

if 3 m's add up to 108, each m must be 1/3 of the total

using algebra
3m = 108

3m/3 = 108/3
m = 108/3

Answer 16

once you figure out what m is, you can find the other ages. they will be m-1 and m+1

Answer 17

thanks i got it :)