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OpenStudy (anonymous):
solve √p=-1. identify any extraneous solutions. Help! i have no idea what 2 do with this question
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OpenStudy (nubeer):
hmm i think just take square on both sides. and get value of p
OpenStudy (jdoe0001):
I'd say is extraneous, because, the \(\sqrt{p}\) looks to me to be referring to the POSITIVE answer from \(\pm \sqrt{p}\) and cannot be negative
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