Question

solve log(base 3)3 + log(base3)x = 5. how would you solve it

Answer 1

First use the rule
\[\log_{a} b+\log_{a} c=\log_{a} bc\]

Answer 2

\[\log_3(3)+\log_3(x)=5\]
\[\log_3(3x)=5\]then write in equivalent exponential form as
\[3^5=3x\]and solve for \(x\)