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OpenStudy (anonymous):
what are the intrcepts of the equation: 2x+(3/2)y+3z=6
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OpenStudy (anonymous):
Kush
OpenStudy (anonymous):
2x+(3/2)y+3z=6 divide by 6,we get 2x/6+3y/12+3z/6=1 x/3+y/4+z/2=1 hence x-intercept is=3 y-intercept is=4 z -intercept is=2
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