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Mathematics 14 Online
OpenStudy (anonymous):

Solve: |5x + 2| + 7 < 19 A. x < 2 and x > -14/5 B. x < 2 and x < -14/5 C. x > 2 and x > 14/5 D. x > 2

OpenStudy (anonymous):

|5x+2|+7<19 |5x+2|<19-7 |5x+2|<12 -12<5x+2<12 -12-2<5x+2-2<12-2 -14<5x<10 Divide by 5 -14/5<x<2 -14/5<x<2 hence x<2,x>-14/5

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