Question

choose the equation of the line with a line passing through (3,-5) and perpendicular to x-2y=2

Answer 1

ok so perpendicular to x-2y = 2

We have -

x-2 = 2y

i.e. x/2 -1 = y

Now comparing with y = mx+c,

m1 = 1/2

Now m1m2 = -1 for perpendicular lines.

Hence slope of perp. line passing through (3,-5) m2

m2 = -1/1/2

=> m2 = -2

Now if x1 = 3, y1 = -5, m2 = -2,

Equation = y-y1 = m2(x-x1)

=> y+5 = -2(x-3)

=> y+5 = 6-2x

i.e. 2x+y-1 = 0 is the answer.

Answer 2

ok so the equation is y=1/2x-7/2 or y=-1/2x-7/2 or y=-2x+1 or y=-2x=11