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tan 5pi/6 square root of three –sqaure root three over three –square root of three 1
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tan 5pi/6 = - tan pi/6 = - (1/2)/[(sqrt(3)/2] = - 1 / sqrt(3) = - sqrt(3) / 3 That last result is gotten by multiplying the numerator and the denominator by sqrt(3)
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