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Find the area inside of one leaf of the rose. r=6sin(4theta)
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So to start can you please graph the equation.
I'm not sure how to do this.
Use a graphing utility to do so. Without a picture of the polar curve it is hard to tell what it looks like, and the interval we must integrate in order to find the area.
remember in polar coordinates the r value that you obtain is the distance from the origin
http://www.wolframalpha.com/input/?i=r%3D6sin%284theta%29 I'll make life easier for us all I guess.
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