Question

What is the solution set of |x + 5| > 1?

x < –6 or x > 6

x < –6 or x > –4

x < –4 or x > –4

x < –4 or x > 6

Answer 1

I'd suggest you square both sides then quadratic equation

Answer 2

but im dealing with absolute value...i dont know if you can do whatever you just said to do

Answer 3

\[(x+5)^2>1 \\ \\ x^2+10x+25-1>0 \\ \\ x^2+10x+24>0 \\ \\ (x+4)(x+6)>0 \\ \\ x=-4 ~~x=-6\]

x<-6 , x>-4

Answer 4

Everytime you see an absolute value with inequalities I suggest you should square both sides

Answer 5

just to mention an alternative method :
|a+b| > c
---> a+b > c or a+b < -c
solve these 2 equations separately to get 2 inequalities