Question

http://prntscr.com/12cff2
B?

Answer 1

i am getting that it opens right, (correct.)
but the vertex is not the same that i get...

Answer 2

\[\Large y^2 = 6x+14 \] right? Idk cos there's a positive sign in front of 6x which seems odd, like maybe a term is missing.

Otherwise you can write it as (by factoring out a 6 on the right)
\[\Large y^2 = 6(x+\frac{ 14 }{ 6})\]

Which gives a vertex \[\large \left( -\frac{ 14 }{ 6 }, 0 \right)\]

Answer 3

to the right
y^2=- opens to the left
x^2=+ opens up
x^2=- opens down