Mathematics
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OpenStudy (anonymous):
solve equation by square root property
y(sqrt2) - 250 = 0
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
y^2 - 250 = 0
y^2 = 250
I'll let you finish up
OpenStudy (anonymous):
@jim_thompson5910 125?
jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
you have to take the square root of both sides and simplify
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jimthompson5910 (jim_thompson5910):
don't forget about the plus/minus
OpenStudy (anonymous):
do i do sq root of 2 and sq root of 250?
jimthompson5910 (jim_thompson5910):
y = sqrt(250)
y = ???
OpenStudy (anonymous):
62500
jimthompson5910 (jim_thompson5910):
square root, not square
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jimthompson5910 (jim_thompson5910):
250^2 = 62500
but the square root, or sqrt, is the opposite
OpenStudy (anonymous):
oh u divide?
jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
square root
OpenStudy (anonymous):
so 250 x 250?
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jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
idk how you're getting that
jimthompson5910 (jim_thompson5910):
square root is not the same as squaring a number
OpenStudy (anonymous):
i never knew that
OpenStudy (anonymous):
so what do i do?
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jimthompson5910 (jim_thompson5910):
example
6 squared = 6^2 = 6*6 = 36
going in reverse
the square root of 36 = sqrt(36) = 6
jimthompson5910 (jim_thompson5910):
see the difference?
OpenStudy (anonymous):
so 250 x 2
jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
y = sqrt(250)
how would you simplify that
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OpenStudy (anonymous):
250 x 250?
jimthompson5910 (jim_thompson5910):
which number in the list below
1, 4, 9, 16, 25, 36, 49, 64, 81, 100
is a factor of 250 ?
OpenStudy (anonymous):
25 @jim_thompson5910
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
so 250 = 25*10
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jimthompson5910 (jim_thompson5910):
which means
y = sqrt(250)
y = sqrt(25*10)
y = sqrt(25)*sqrt(10)
y = 5*sqrt(10)
jimthompson5910 (jim_thompson5910):
so the two solutions are
y = 5*sqrt(10)
or
y = -5*sqrt(10)
jimthompson5910 (jim_thompson5910):
don't forget about the plus/minus
OpenStudy (anonymous):
how do u know which one to choose?
jimthompson5910 (jim_thompson5910):
both are solutions
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jimthompson5910 (jim_thompson5910):
since both satisfy y^2 - 250 = 0
OpenStudy (anonymous):
thanks!
jimthompson5910 (jim_thompson5910):
yw