Find the value of x so that the line passing through the points will have the given slope: (x, 6) and (10, -3) with a slope of -3/2.
A. -13
B. 4
C. 13
D. -12
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OpenStudy (anonymous):
@luckythebest
how do we do this ?
OpenStudy (anonymous):
What is formula of slope?
OpenStudy (anonymous):
Slope = y2-y1/x2-x1.
OpenStudy (anonymous):
ok.
and slope given is -3/2
so -3/2 = y2-y1/x2-x1. try and solve. :)
OpenStudy (anonymous):
what does y and x =
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OpenStudy (anonymous):
x1 = x, y1 = 6, x2 = 10, y2 = -3
and -3/2 = y2-y1/x2-x1
Solve for x.
OpenStudy (anonymous):
i dont understand :( but ill try
OpenStudy (anonymous):
-3/2 = -3-6/10-x
OpenStudy (anonymous):
-3-6=-9
OpenStudy (anonymous):
yep.
-3/2 = -9/10-x
-3(10-x) = 2.-9
at least now? :P
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OpenStudy (anonymous):
so x = 2.9 ? how did you get 2.9 ?
OpenStudy (anonymous):
^ is the equation.
-3 x (10-x) = 2 x -9
i.e. -30 + 3x = -18
OpenStudy (anonymous):
that what i got was 30 that why i asked you how you got 2.9
OpenStudy (anonymous):
ok ok i get it. :P
2.-9 i meant 2 x -9 ( . means multiplication)
OpenStudy (anonymous):
so now we have -9/-18 ?
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OpenStudy (anonymous):
Ok wait here.
-3/2 = -9/10-x
-3(10-x) = 2(-9)
=> -30 + 3x = -18
=> 3x = 12 i.e. x = 4.