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OpenStudy (anonymous):
Factor by grouping. 3x2 + 7x – 6 A. (3x – 2)(x – 3) B. (3x – 2)(x + 3) C. (x + 3)(3x + 2) D. (3x + 2)(x – 3)
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OpenStudy (anonymous):
it's a (3x-2)(x-3
OpenStudy (anonymous):
it's B. because (3x – 2)(x + 3)=3x^2+9x-2x-6 simplify = 3x^2+7x-6
OpenStudy (anonymous):
\[3x^2 + 7x – 6\] \[(x+3) (3 x-2)\]
OpenStudy (anonymous):
ok
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