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OpenStudy (ketz):

f=x'y'z+(x'y'z)'. Simplify the boolean expression.

OpenStudy (ketz):

It's urgent...

OpenStudy (anonymous):

hi please reput this question in the math section

hartnn (hartnn):

your next math questions should go in http://openstudy.com/study#/groups/mathematics as for this, you use the identity, A+A' = 1 so, f=x'y'z+(x'y'z)' = 1 (where x'y'z can be considered as A)

OpenStudy (anonymous):

hey @hartnn

hartnn (hartnn):

hi, jack :)

OpenStudy (anonymous):

came back from long training

hartnn (hartnn):

welcome back! great to have you again on OS :)

OpenStudy (anonymous):

i happy to be back and i missed all my friends on os. that means u to

hartnn (hartnn):

:)

OpenStudy (anonymous):

so how was everything when i was gone

hartnn (hartnn):

lets not talk here, its a question...

OpenStudy (anonymous):

true so were should we talk

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