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f=x'y'z+(x'y'z)'. Simplify the boolean expression.
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It's urgent...
hi please reput this question in the math section
your next math questions should go in http://openstudy.com/study#/groups/mathematics as for this, you use the identity, A+A' = 1 so, f=x'y'z+(x'y'z)' = 1 (where x'y'z can be considered as A)
hey @hartnn
hi, jack :)
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came back from long training
welcome back! great to have you again on OS :)
i happy to be back and i missed all my friends on os. that means u to
:)
so how was everything when i was gone
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lets not talk here, its a question...
true so were should we talk
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