Question

x2+6x-2=0

Answer 1

Same as last problem! Use the quadratic formula I provided.

Answer 2

quadratic formula:

x = (-9 +- sqrt(45))/2

= (-9 +- 3*sqrt(5))/2

= 3(-3 +- sqrt(5))/2


Is this correct for the last question? @abb0t

Answer 3

\[x= \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 4

I don't know, nathan! This is a new problem.

Answer 5

Given: ax² + bx + c = 0
Quadratic Formula: x = [-b ± √(b² - 4ac)] / 2a

Given: 1x² + 6x + 2 = 0
Means: a = 1, b = 6, c = 2

x = [-b ± √(b² - 4ac)] / 2a
x = [-(6) ± √((6)² - 4(1)(2))] / 2(1)
x = [-6 ± √(36 + -8)] / 2
x = [-6 ± √28] / 2
x = [-6 ± √(4 * 7)] / 2
x = [-6 ± 2√7] / 2
x = -3 ± √7

Answer 6

this is so confusing to me