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Find the ninth term of the geometric sequence if a1 = 7 and r = 2
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\[7\times 2^8\] should do it
multiply a1 times r to get the a2 then by r again to get a3...
1792
a1 = 7 a2 = 7x2 = 14 a3 = 14x2= 28 .... a9 = 896x2 = 1792 :D or just 7x2^8 yea :P
Thank you all of you :)
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