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OpenStudy (anonymous):
find all solutions for Sin^2x - 2sinx - 3 = 0 on the interval [0 , 2pi )
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sam (.sam.):
You can factor it or use quadratic equation for that, what's your thought?
OpenStudy (anonymous):
can u show me by doing on Draw board ?
sam (.sam.):
Factor it like this, \[(\sin(x)-3)(\sin(x)+1)=0\] Then set each bracket equals to zero and solve for "x"
sam (.sam.):
|dw:1367203095000:dw|
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