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\[\frac{ a }{ \sin A }=\frac{ b }{ \sin B }\] \[\frac{ 62 }{ \sin 54 }=\frac{ 75 }{ \sin B }\] 62 sin B = 75 sin 54 sin B = 0.9786 B = 78.1 or (180 - 78.1 = 101.9 there are 2 solutions: Solution 1: <B = 78.1 <C = 180 - 78.1 - 54 = 47.9 \[\frac{ a }{ \sin A }=\frac{ c }{ \sin C }\] \[\frac{ 62 }{ \sin 54 }=\frac{ c }{ \sin 47.9 }\] c sin 54 = 62 sin 47.9 c = 56.9 Solution 2: <B = 101.9 <C = 180 - 101.9 - 54 = 24.1 \[\frac{ a }{ \sin A }=\frac{ c }{ \sin C }\] \[\frac{ 62 }{ \sin 54 }=\frac{ c }{ \sin 24.1}\] c sin 54 = 62 sin 24.1 c = 31.3
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