Question

Find the common ratio for the geometric series 1/2,-1/4,1/8,-1/16....

Answer 1

Formula

r= t1/tn-1

tn=t1r^n-1

Answer 2

\[ratio=\frac{ 2^{nd} term }{ 1^{st} term } = \frac{ 3^{rd} term }{ 2^{nd} term }\]
and so on

Answer 3

r =-1/2

Answer 4

Thought t1=1/2

Answer 5

-1/4 over 1/2
=-1/4x2
= -1/2

Answer 6

Thanks

Answer 7

WHat about 1/8

Answer 8

\[\frac{ \frac{ 1 }{ 8 } }{ -\frac{ 1 }{ 4 } }\] will give the same result as
\[\frac{ -\frac{ 1 }{ 4 } }{ \frac{ 1 }{ 2 } }\]

Answer 9

ok cool give this guy a medal please @RadEn

Answer 10

So -1/16/1/8