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Write the first five terms of the geometric sequence where t1 = -3, and r = -1.
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\[\large T_n=a_1r^{n-1}\]
N=?
Since \(T_1=-3\), Second term will be \[T_2=(-3)(-1)^{2-1}=3\] Third term will be \(T_3\)
n is the number of term you are using
For term 3 n will be 3
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\(a_1=First~term\)
t3=9?
-3,3,9,15,21
\[T_3=(-3)(-1)^{3-1} =?\\ \\ T_4=(-3)(-1)^{4-1}=?\]
T3=9 T4=15
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Why would \(T_3=9?\)
(-3)(-1)^3-=2
Cause I thought if t1=-3 t2=3 t3 would=9 since the common difference is 6?
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