Question

Find a pair of factors for each number by using the difference of two squares.
a. 45
b. 77
c. 112

Answer 1

@snowman97,

Answer 2

yea

Answer 3

can u help me in this

Answer 4

yea

Answer 5

ok

Answer 6

u half to pick one

Answer 7

b

Answer 8

ok u got it ur right b 77

Answer 9

45=49-4

Answer 10

u half to find two squres for all

Answer 11

do you know what number squares to give 49?

Answer 12

4

Answer 13

this is my answer but my teacher mark it wrong

Answer 14

45plus49-4equal7+2.7-2equal 9 times 5



77equal 81-4equal 9+2.9-2equal 11times 7



112equal 121-9equal 11plus311-3equal 14 times 8


Comment: Don't use words. Use the symbols.

Answer 15

\[45 = 49-4=7^2-2^2=(7-2)(7+2)=5\times9\]

Answer 16

beside the word is the answer right

Answer 17

wont it be 8 times

Answer 18

@snowman97 \(5\times8=40\)

Answer 19

what about B and c @UnkleRhaukus

Answer 20

wate i did that wrong

Answer 21

\[77=a^2-b^2=(a-b)(a+b)=\]

Answer 22

40 right

Answer 23

can you find \(a\) and \(b\)

Answer 24

my computer acting weird give me min for the answer

Answer 25

77= 81 - 4= 9+ 2. 9-= 11 x 7

Answer 26

@UnkleRhaukus

Answer 27

do you mean

77= 81 - 4= 9^2- 2^2 = (9+2)(9-2)=

?

Answer 28

18

Answer 29

???//?

Answer 30

i don't know

Answer 31

he didnt give u da answer he dosnet know it

Answer 32

dang dis is hard

Answer 33

well do u know it

Answer 34

i know it's hard

Answer 35

77=81-4= 9^2- 2^2 = (9+2)(9-2)= 112

Answer 36

c. 112