[1] FeSO4∙(NH4)2SO4∙ 6H2O + H2C2O4∙ 2H2O --- FeC2O4 + (NH4)2SO4 + H2SO4 + 8H2O

[2] 6 FeC2O4 + 3H2O2 + 6K2C2O4∙ H2O --- 4 K3[Fe(C2O4)3]∙ 3 H2O + 2 Fe(OH)3 + 6 H2O

[3] 2 Fe(OH)3 + 3 H2C2O4∙ 2H2O + 3 K2C2O4∙ H2O ---- 2 K3[Fe(C2O4)3]∙ 3H2O + 9 H2O

4.0g of ferrous ammonium sulphate, FeSO4 ∙ (NH4)2SO4 ∙ 6H2O is used. Since the oxalate is in excess, calculate the theoretical yield of the iron complex.

NOTE: We assume 100% conversion efficiency, going from 1 reaction to the next.

Question

[1] FeSO4∙(NH4)2SO4∙ 6H2O + H2C2O4∙ 2H2O ---> FeC2O4 + (NH4)2SO4 + H2SO4 + 8H2O

[2] 6 FeC2O4 + 3H2O2 + 6K2C2O4∙ H2O ---> 4 K3[Fe(C2O4)3]∙ 3 H2O + 2 Fe(OH)3 + 6 H2O

[3] 2 Fe(OH)3 + 3 H2C2O4∙ 2H2O + 3 K2C2O4∙ H2O ----> 2 K3[Fe(C2O4)3]∙ 3H2O + 9 H2O

4.0g of ferrous ammonium sulphate, FeSO4 ∙ (NH4)2SO4 ∙ 6H2O is used. Since the oxalate is in excess, calculate the theoretical yield of the iron complex.

NOTE: We assume 100% conversion efficiency, going from 1 reaction to the next.