Question

Test whether the following function is odd/even/either/neither
\LARGE \frac{\sin^3x}{[\frac {x}{\pi}]+\frac{1}{2}}

Answer 1

@ParthKohli @AravindG

Answer 2

check putting -x instead of x, if the fucntion changes, then it's odd if not then even

Answer 3

it is not that easy

Answer 4

sorry keyboard nt working

Answer 5

:/

Answer 6

sin(-x)=-sin(x)

Answer 7

\[\LARGE f(-x)=\frac{-\sin^3x}{[\frac {-x}{\pi}]+[\frac{1}{2}]}\]

Answer 8

so... it is?

Answer 9

u say?

Answer 10

if f(x)=f(-x) it's even

Answer 11

how is it =fx?

Answer 12

it is odd

Answer 13

:/

Answer 14

f(x) refers to the "function of x"

Answer 15

yes

Answer 16

your result is \[f(x)neqf(-x)\]

Answer 17

not equal

Answer 18

if it would be equal then even

Answer 19

@terenzreignz