Question

Pre-calculus problem please help!

Answer 1

Solve the system

Answer 2

solve for y in the first equation then substitute so

2x + y = 5 => 2x -2x + y = 5 - 2x => y = 5 - 2x

x^2 -5 + (5 - 2x) = 0 => x^2 - 2x = 0 => x (x - 2) = 0 x = 2, 0

when x = 0, y = 5
when x = 2, y = 1

Answer 3

thanks