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Precalculus
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f(x)=3csc(pi/4x+pi/8) I need to know a. the period of this function, b. the sequence of transformations from g(x)= csc(x) -> F(x) = 3 csc(pi/4x+pi/8)
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Same as before. Factor out the pi/4 first.
The period can be found with this formula \[Coefficient` of `x = \frac{2 \pi}{period}\]
ok so its starts with the vert stretch from 1 -> 3, then a horizontal stretch by a factor of \[\frac{ \pi }{ 4}\]
yes
then a shift to the left of......and I'm stuck. i want to say \[\left(\begin{matrix}\pi \\ 2\end{matrix}\right) -\left(\begin{matrix}\pi \\ 42\end{matrix}\right)\]
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Shift to left of pi/2
is that from pi/4* pi/8?
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