Question

find the infection points for f(x)=8x+3-2sinx

Answer 1

find the second derivative. that would be your inflection point(s). an inflection point by definition is a point on a curve at which the second derivative changes sign.

Answer 2

yes I found the second derivative but I don't know how to get the critical points for f"(x)=8+2sinx

Answer 3

set it equal to zero and find the value's where \(sin(x) = \frac{1}{4}\)

Answer 4

but I have sinx=-4