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Prove that among any 18 consecutive three - digit numbers there is at least one number which is divisible by the sum of its digits.
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@abb0t HELP ME Sir
@mathstudent55 Sir Help Me
Um, smallest three digit number is 100.
the sum of those is 1, and highest is 999 = \(9^3\) = 27. so range is 1-27
ok
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