Question

Find the cotangent of both angle A and angle B.

http://roads.advancedacademics.com/contentserver/content/roadssection/279559/questions/assessments/r-trigonometricratiosshortanswerquiz/geometry_8.2.11_quiz_final_8q.gif

I believe the answer is

cot A = 12/5; cot B = 5/12.

In a comment, I'll write how I got this answer. Could someone correct me if I am wrong? Thanks :)

other possible answers:

A. cot A = 5/12; cot B = 12/5
B. cot A = 5/13; cot B = 13/5
C. cot A = 12/5; cot B = 5/12
D. cot A = 13/5; cot B = 5/13

Answer 1

\[\cot a = \frac{ 1 }{ \tan a } = \frac{ adjacent }{ opposite } = \frac{ 24 }{ 10 } \div 2 = \frac{ 12 }{ 5 }\]

\[\cot a = \frac{ 1 }{ \tan a } = \frac{ adjacent }{ opposite } = \frac{ 10 }{ 24 } \div 2 = \frac{ 5 }{ 12 }\]

Thanks so anyone who can help me!

Answer 2

whoops that was supposed to be cot and tan B

Answer 3

you're correct :)

Answer 4

Really? Awesome thanks! :)