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Mathematics 17 Online
OpenStudy (anonymous):

does (k^e)/(k^pi) converge or diverge

OpenStudy (anonymous):

\[\frac{k^e}{k^{\pi}}=k^{e-\pi}\]

OpenStudy (anonymous):

or if you prefer \[\frac{1}{k^{\pi-e}}\]

OpenStudy (anonymous):

Thank you! and it diverges because -e+ pi is less than 1

OpenStudy (anonymous):

yes it does

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