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Factor completely 121x^2 - 44x + 4 Choose one answer. a. (11x - 2)2 b. (2x - 11)2 c. (11x - 2)(11x + 2) d. None of the above
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D again?
121x^2 - 44x + 4 = 0 USE FORMULA ( a^2 - 2ab + b^2) = ( a - b) ^2 Here a = 11x b = 2 ( 11x - 2) ^2 = 0 So 11x = 2 x = 2/11 ANSWER
So it be A then?
Yes A seems about right
Ahh thank you guys! I love algebra but I hate these factoring ones..
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( 11x - 2) ^2
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