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Mathematics 22 Online
OpenStudy (anonymous):

csc^4x-cot^4x=csc^2x+cot^2x

OpenStudy (loser66):

\[(csc^2x)^2 - (cot^2x)^2\]= \[(csc^2x+cot^2x)(csc^2x-cot^2x)\]

OpenStudy (loser66):

let the first tem aside, I just manipulate the second term and make it =1 so you get the answer, right?

OpenStudy (loser66):

\[= \frac{ 1 }{ \sin^2x }-\frac{ \cos^2x }{ \sin^2x }=\frac{ 1-\cos^2x }{ \sin^2x}= \frac{ \sin^2x }{ \sin^2x }=1\] so your stuff is proved

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