Question

The area of room A is (5x^2 – 7x – 6) ft^2. Room B has an area of (8x^2 + 6x – 1) ft^2. If room A is the larger room, how much greater is the area of room A than the area of room B?

Answer 1

\[5x ^{2}-7x-6>8x ^{2}+6x-1\]
\[-3x ^{2}-13x-5>0\]
\[3x ^{2}+13x+5<0\]
\[\Delta=13^{2}-4\times3\times5=109\]
\[x=\frac{ -13-\sqrt{109} }{ 2\times3 }=-3.9\]
\[x=\frac{ -13+\sqrt{109} }{ 2\times3 }=-0.4\]
the difference of area is\[-3x ^{2}-13x-5\]
\[-3(-3.9)^{2}-13(-3.9)-5=-45.63+50.7-5=0.07\]
\[-3(-0.4) ^{2}-13(-0.4)-5=-0.48+5.2-5=-0.28\]
since room A is larger than B
so 0.07 is the answer.
Very apologize if I'm wrong.

Answer 2

3rd

Answer 3

sure

Answer 4

I'm not quite understand the question but \[5^{1+10}\]\[5^{2+9}\]\[5^{3+8}\]