Question

3-4ln(8x+1)=12

Answer 1

\[\ln(8x+1)=\frac{ 12-3 }{ -4 }\]
\[8x+1=e ^{\frac{ 9 }{ -4 }}\]
\[8x=\frac{ 1 }{ e ^{\frac{ 9 }{ 4 }} }-1\]
\[x=\frac{ 1 }{ 8e ^{\frac{ 9 }{ 4 }} }-\frac{ 1 }{ 8 }\]

Answer 2

pt 1

Answer 3

pt 2