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Mathematics 15 Online
OpenStudy (anonymous):

How many ten–letter permutations can be formed from the letters of the word BOOKKEEPER?

OpenStudy (anonymous):

Permutations of 10 letters taken 3 a time = 10 x 9 x 8 = 720

OpenStudy (anonymous):

A)1,814,400 B)10 C)151,200 D)75,600

OpenStudy (anonymous):

720 wasn't one of the options. I get what your saying though.

OpenStudy (anonymous):

Those are your selection of answers?

OpenStudy (anonymous):

Yeah, I'm sorry. I thought I knew it. I apologize

OpenStudy (anonymous):

i dont quite understand your writing. please explain?

OpenStudy (anonymous):

\[\frac{ 10! }{2!*2!*3!}= 151200\]

OpenStudy (anonymous):

thank you!!!

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