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OpenStudy (anonymous):
if a circle of radius 13 is made to roll along the x-axis, what is an equation for the path of the center of the circle?
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OpenStudy (hunus):
|dw:1367354040032:dw| So the path of the center of the circle is a straight line that is 13 units above the x-axis
OpenStudy (hunus):
Since there is no rise of the slope (m = 0) the equation will be of the form \[y = mx + b = 0x + b = b\] \[y=b\] So what would b be in this scenario?
OpenStudy (anonymous):
13?
OpenStudy (hunus):
Yup
OpenStudy (anonymous):
Thank you!
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OpenStudy (hunus):
Yup :)
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