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Precalculus
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2(16^x)-9(4^x)+7=0
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whats the question
I need find x
to*
rewrite 2(16^x) as \[2(2^4)^{x}\]
get it in terms of base 2 and then you can combine them using exponent rules
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okay I'll try that I kept changing it to base 4 because the other possible term is base 4 too
|dw:1367366053654:dw|
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