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how do u know when a graph has two irrational solutions ?
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Well uh, if b^2-4ac of the quadratic equation is not a perfect square.
is this irrational ?
sorry cannot open it; if u can just roughly draw the graph
|dw:1367374959971:dw|
Ok as we can see that this graph does not touch x-axis at all. This tells us that the graph does not have any real solution of x.(if y = 0, there is no real solution of x) (Neither integers nor real numbers.) And if x cannot be real, it has to be imaginary. Hence this graph is irrational.
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