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Linear Algebra
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8n - (-2)/7 = 6 I have no idea how to go about solving this.
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just think its -(-a) = a an identity. also use the cross multiplication for 7 in the denominator. and solve for n
\[\frac{ 8n }{ 7 }=6 ; 8n= 6*7 ; n = \frac{ 42 }{8 }\]
8n-(-2)/7=6 multiply by 7, 56n-(-2)=42 56n+2=42 56n=42-2=40 n=40/56=5/7
Oh, I see, well thank you c:
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